Word problom???

This table shows the results of a poll concerning a new city ordiance.








Poll Result chart





Opinion Number


______________________________________...





strongly in favor 6





Mildly in favor 12





Mildly opposed 28





Strongly opposed 9





No opinion 5








(the word problome)





Assum that the people polled represent a random sample of all the people living in the city. If the total population of the city is 50,000 people, how many people would you expect to be strongly in favor or the ordiance?





(A) 500 residents





(B) 5000 residents





(C) 10,000 residents





(D) 15,000 residents

Word problom???
6/60 = x/50,000





x = (6)(50000) / (60) = 5000





So your answer would be (B) 5000 residents
Reply:question poorly worded.





6 out of 60 were strongly in favor (1 out of 10)





so I would say "b" which is 1/10 of 50,000
Reply:That's two different ways to get the same answer, both of which assume there were 60 people in the sample. But all you can do is to add up the answers to arrive at the sample population, since they question doesn't really say.
Reply:B
Reply:Answer=B





6/60= 10%





10% of 50,000= 5,000
Reply:B) 5000





6 out of 60 people were strongly in favour. This is 10%


(6÷60)X100 = 10%





10% X 50 000


= 0.1 X 50 000


= 5000





That gives you the answer of 5000 people.