2 math questions please help?

Three women and two men are waiting for an interview concerning a job opening at an advertising agency. There is only enough time before lunch for two people to be interviewed. Two people are chosen at random. What is the probability that both of these people are women?





a) 3/5 b) 3/10 c) 5/3 d) 3/20








To review types of percent problems, determine which statement below is NOT true?





a) To find what percent 15 is of 65, divide 15 by 65 and change your answer to a percent.





b) If you are told that 5% of a number equals 200, divide 200 by 0.05 to find the original amount.





c) To find the sales price of a video player that is discounted by 25%, multiply the original price by 0.75.





d) If 30% of a number equals 90, multiply 90 times 0.30 to find the original number.

2 math questions please help?
There are 3 women and 2 men so 5 people in all.





There are 5C2 = 5*4/2 = 10 ways to select 2 people from 5





There are 3C2 = 3 ways of selecting 2 women from 3.





So the probability of selecting 2 women for the interview is 3/10 or answer (b)





-----





(d) is false
Reply:1: b


2: d
Reply:1.


Label the women A, B, C.


Label the men X, Y.





Probability = number of desired outcomes / total possible outcomes.





Number of desired outcomes is 3


AB


AC


BC





Total possible outcomes is 10:


AB


AC


AX


AY


BC


BX


BY


CX


CY


XY





Answer: 3/10





Problem 2





If 30% of a number equals 90, DIVIDE 90 by 0.30 to find the original number.





Answer: d)
Reply:1. b


2. d
Reply:Q 1= d) 3/20





NOT true


a)


d)
Reply:the first question answer is choice b -----%26gt; c(3,2)/c(5,2) = 30%