Tuesday, July 28, 2009

Probability advance algebra math problem help?

Three cards are selected at random from a group of 7. Two of the cards have been marked with winning numbers.





a. What is the probability that exactly 1 of the 3 cards has a winning number?





b. What is the probability that at least one of the 3 cards has a winning number?





c. What is the probability that none of the 3 cards will have a wining number?





d. What relationship is there between the answers to parts b and c?





Please show your work and thanks in advance!

Probability advance algebra math problem help?
a)


2/7 * 5/6 * 4/5 = 40/210


5/7 * 2/6 * 4/5 = 40/210


5/7 * 4/6 * 2/5 = 40/210





= 120/210 = 12/21





b)





as above + chance that both special cards are chosen:





2/7 * 1/6 * 5/5 = 10/210 * 3 = 30/210


AND THREE WITH SAME PROB...(AS ABOVE)





120/210 + 30/210 = 150/210 = 15/21





c)


5/7 * 4/6 * 3/5 = 60/210





D)


they together make all the combinations. the chance of getting 1 or more %26amp; getting none add to make 100%.


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