Statistics question...?

For a normal distribution,





a. Find the z-score for which a total probability of 0.02 falls more than z standard deviations (in either direction) from the mean.





b. For this z, explain why the probability more than z standard deviations above the mean equals 0.01.





c. Explain why µ + 2.33σ is the 99th percentile.





*Note:


The z-score for a value x of a random variable is the number of standard deviations that x falls from the mean µ. It is calculated as





z = (x- µ) / (σ)

Statistics question...?
a. ) read the z table backward find z score associated with area of .01 youll find the answer is z=2.33


b.) the curve has been defined such that 98% of area is between 0+/- 3 standard deviations of width 1


c.) u+2.33s=z implies p(-infinity to z)=.99 thus 99% of area under curve is to left of z