How would i do this c++ program without using boolean?

# include %26lt;iostream.h%26gt;


# include %26lt;iomanip.h%26gt;


#include %26lt;ctype.h%26gt; // needed for toupper


#include %26lt;stdlib.h%26gt;// needed for rand


#include %26lt;fstream.h%26gt;





using namespace std;





int main ( )


{





int num[20]={0};





const int numLength = 20;





for(int count = 0;count %26lt; 20;count++)


{


cout%26lt;%26lt;"enter 20 numbers with


repeating numbers"%26lt;%26lt;endl;


do{


cout%26lt;%26lt;"enter number "


%26lt;%26lt;(count+1)%26lt;%26lt;": "%26lt;%26lt;endl;


cin %26gt;%26gt; num[count];


}


while (num[count]%26lt;10


|| num[count] %26gt; 100);





}


cout %26lt;%26lt; "The original set of numbers were: ";





for(int countfun = 0;countfun


%26lt; 20;countfun++)


{


cout %26lt;%26lt; num[countfun]


%26lt;%26lt; setw(3);





}





cout %26lt;%26lt;"\nThe different numbers


from the set of integers are: ";





return 0;


}





I'm supposed to have 20 random numbers with repeating variables.





Example: My numbers 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2





Original set of numbers: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2


New set of numbers: 1 2





I can't use boolean to remove the duplicates. How would I do this? Thanks.

How would i do this c++ program without using boolean?
After you assign a number into the array, test whether that number is equal to any other array member. If it is a match, then do not increment to the next array member, because you want to assign the next number into that same array member. If it is not a match then you assign the next number to the same array member.





For example, the value of num[0] is 1 and you assign 1 into another array member, here's the test:


for(int i=0; i%26lt;count; i++)


if (num[i] == num[0]) count--;





Now you might have another problem, because each time you decrement "count", your other loop "for(int count = 0;count %26lt; 20;count++)" will run an extra iteration. That problem can be solved by using a variable such as "max" instead of the literal number "20", and decrementing "max" when you decrement "count". So now the test will look like this:


for(int i=0; i%26lt;count; i++)


if (num[i] == num[0])


{


count--;


max--:


}
Reply:This sounds like a class project, so I'm not going to give you any code so that you won't be accused of cheating. That being said, here are a couple of solutions.





Get the instructor to define "can't use boolean." Are you not allowed a boolean variable? What about a method that returns a boolean?





If you can use a method, that is how I would do it:


bool duplicateFound(int* original_set, int num_to_check)





if that is not allowed, remember that in C++, boolean is really an integer. False is 0, anything else is true. But this is really cheating.





How about a recursive method that returns the duplicate?





int recursiveCheck(int* num_to_check, num)


{


//check the first number and you are not at the end of the array


// if check fails, increment the pointer and call this function


}