Help! C Program probs....?

//WHATS WRONG WITH MY CODE?





#include %26lt;stdio.h%26gt;


#include %26lt;stdlib.h%26gt;


#include %26lt;time.h%26gt;


#include %26lt;string.h%26gt;


#include %26lt;conio.h%26gt;


int main ()


{


int operand[19];


int ans;


int a,b;


int operation;


/* initialize random seed: */








srand ( time(NULL) );


for(a = 0;a%26lt;10;a++)


{


operand[a] = rand() % 10 + 1;


operand[a+1]= rand() % 10 + 1;


b = rand() % 1 + 1;


if(b == 0) //THE OPERATION IS SUBTRACTION


{


printf("%d - %d = ",operand[a],operand[a+1]);


scanf(" %d ", %26amp;ans);


else //ELSE THE OPERATION IS ADDITION


printf(" %d + %d= ",operand[a],operand[a+1]);


scanf(" %d ", %26amp;ans);


}


}


getch();


return 0;


}





/* I WANT TO CREATE A PROGRAM THAT RANDOMIZE A NUMBER AND ALSO IF THE VARIABLE B WILL DECLARE 0 THE OPERATION IS SUBTRACTION BUT IF 1 THE OPERATION IS ADDITION, I THINK MY LOGIC IS RIGHT BUT THE PROGRAM ALWAYS SAY THAT THERE IS A SYNTAX ERROR BEFORE "ELSE" */

Help! C Program probs....?
Your syntax error is that you didn't close the if statement before else





You want


if(b == 0) //THE OPERATION IS SUBTRACTION


{


printf("%d - %d = ",operand[a],operand[a+1]);


scanf(" %d ", %26amp;ans);


} /* %26lt;%26lt;------------------------------ Add that */


else //ELSE THE OPERATION IS ADDITION


{ /* %26lt;%26lt;------------------------------ Add that */


printf(" %d + %d= ",operand[a],operand[a+1]);


scanf(" %d ", %26amp;ans);


}


} /* %26lt;%26lt;------------------------------ Delete that */


Also, I think you want


b = rand() % 2





As it is now


b = rand() % 1 + 1





You'll get a random number, divide it by 1, which will be remainder 0 every time, and then add 1, so it will be 1 every single time.
Reply:conio.h is not a standard header. make sure you have the necessary libs.





And, as other have rightly noticed, there should be braces around 'else //ELSEE THE OPERATION IS ADDITION'. That should look like '} else { //ELSE THE OPERATION IS ADDITION'.
Reply:Well,





if(b == 0) //THE OPERATION IS SUBTRACTION


{


printf("%d - %d = ",operand[a],operand[a+1]);


scanf(" %d ", %26amp;ans);


else //ELSE THE OPERATION IS ADDITION


printf(" %d + %d= ",operand[a],operand[a+1]);


scanf(" %d ", %26amp;ans);


}





Looks wrong. The { and } that should encapsulate the "if" part of the statement is including the "else" part as well, which won't work. Try





if(b == 0) //THE OPERATION IS SUBTRACTION


{


printf("%d - %d = ",operand[a],operand[a+1]);


scanf(" %d ", %26amp;ans);


}


else //ELSE THE OPERATION IS ADDITION


{


printf(" %d + %d= ",operand[a],operand[a+1]);


scanf(" %d ", %26amp;ans);


}





instead.
Reply:The format of the if statement is


if ()


{


}


else


{


}





I think you have


if ()


{


else


}