Sunday, August 2, 2009

Statistics question....mode median, mean I think?

I am having trouble understanding the concept of this. Can anyone help me?


To test the quality of it's paper clps , a manufacture randomly collects 100 paper clips from each batch. After 10 random samples, the following results are obtained.





Sample A B C D E F G H I J


defective 2 1 2 0 1 2 1 4 2 3





A) What percentof the paper clips are defective in sample A?





B) What percent of the paper clips are defective in the total of samples A to J?





c) If the sample K is taken, how many defective paperclips might you expect? Select the best answer for each number.


6 : yes, no, maybe


3: yes, no, maybe


2: yes, no, maybe


0: yes, no, maybe





Any help in explaining this would be great. I can't get ahold of the math teacher and I want to finish this lesson. Haven't even gotten to the real questions yet !

Statistics question....mode median, mean I think?
1. 2% of paper clips are defective in sample A. there are 100 paper clips in each sample, if 2 are defective, 2/100 = 0.02 or 2%





2. 1.8% of the paper clips are defective in A through J. 2+1+2+0+1+2+1+4+2+3 = 18, 100+100+100+100+100+100+100+100+100+100 = 1000, 18/1000 = 0.018 or 1.8%





3. since 2 is the closest to the average of 1.8% of the paper clips being defective, that would be the most likely number of paper clips defective.
Reply:A) There are 100 clips in sample A and 2 are defective. What's that percentage?





B) Add up the number of defectives and divide by total number, then convert decimal to percent
Reply:A. 2 out 100 is 2 percent.


B. 18 out of 1000 = 1.8 percent


Now based on that information, what is the most likely to occur in you 11th sample which is labeled K.


it would be 2
Reply:A) 2 defective out of 100 = 2%


(just divide the number of defective by the total number)





B) 1.8%: add up the defective %26amp; divide by the total number, so:


(2+1+2+0+1+2+1+4+2+3)/1000 = 18/1000 = .018


which is equivalent to 1.8% (.018 = 1.8*100/100)





C) based on the average % which is 1.8, I would expect around 2 defective


so 6: no


3: no


2: yes


0: no


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