Sunday, August 2, 2009

I am having trouble with a few statistics problems. Can someone help me out?

1 Solve the problem.


Which of the following cannot be a probability?





A. square root of 5/3


B. -87


C. 0


D. 0.001





2. Solve the problem.





A single six-sided die is rolled. Find the probability of rolling a number less than 3.





A. 0.5


B. 0.333


C. 0.25


D. 0.1





3. Solve the problem.





Classify the statement as an example of classical probability, empirical probability, or subjective probability. The probability that it will rain tomorrow is 24%.





A. empirical probability


B. subjective probability


C. classical probability





4. Solve the problem.





In a survey of college students, 880 said that they have cheated on an exam and 1721 said that they have not. If one college student is selected at random, find the probability that the student has cheated on an exam.





A. 260/880





B. I 721/2601





C. 880/2601





D. 2601/1721

I am having trouble with a few statistics problems. Can someone help me out?
1: A and B cannot be probabilities since A%26gt;1 and B%26lt;0





2: B as 2 numbers out of 6 are less than 3 (2/6=1/3=0.333)





3: This isn't a very good question but I'd say the answer is A since these statements are normally (but not always) based on observations.





4: C since 880 students cheated out of 880+1721=2601 total students.
Reply:EDITED





1) A. and B. cannot be probabilities.


A probability must be between 0 and 1 inclusive.





2) B. 0.333


Rolling a number less than 3 means rolling a 1 or a 2 so there are 2 "successful" outcomes out of 6 possible outcomes = 2/6 = 1/3 = 0.333 approximately.





3) A. empirical probability


If it is based on prior weather conditions and forecasting (as weather forecasts are usually). The answer is B. "subjective probability" if it's not based on previous empirical data (e.g. if you just have a "hunch").





4) C. 880/2601


The number of "successful" outcomes (having cheated) divided by the total number of outcomes (880+1721=2601).
Reply:1





probabilities are between 0 and 1. this is an axiom of probability. as such sqrt(5/3) and -87 are not probabilities because they are not between 0 and 1.





2.





the numbers less than three on a fair six sided die are 1 and 2. you have P(rolling a 1) = 1/6, P(rolling a 2) = 1/6, the sum is 1/3





3.





i'd say empirical because this value is based on observed data and models to give an estiamte of the probability.





4.





probability is the number of success divided by total possible outcomes





880 / (880 + 1721) = 880 / 2601 = 0.3383314


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