Need desperate help with algebra?

I need help dealing with probability :


(IDK what this means)You roll a blue number and a green number cube. Find the probability. Problems :


P(blue even and green even)





Suppose you choose a tile from a bag containing 2 A's, 3 B's and 4 C's. You replace the first tile in the bag and then choose again. Find each probability. Problems:





P(B and C)





You select a card at random containing these letters P R O B A B I L I T Y. With out replacing the card you chose the second card. Find each probability. Consider Y to be a vowel.





P ( A then A)





I have no clue what to do , please help the person who helps will give 10 points.

Need desperate help with algebra?
Well lets see


on a number cube there are 3 odds, 3 evens, so its 50/50


but with too you could have : 1even 1 odd, 2 evens, or 2 odds, with their being a 1/3 chance of each of those combinations.


So the probabability of a Blue even and a green even are 1/3.





these are easy multiply: 2x3x4=24, theres 24 different combinations, so any one of these combinations have a 1/24 chance of occuring


So the probability of b and c is 1/24





There are 11 letters in probability, and 2 i's and 2'b





in order


p=1/11


r=1/10


o=1/9


b=2/8


a=1/7


b=1/6


i=2/5


l=1/4


i=1/3


t=1/2


y=1/1





since your not putting the card back the number on the right decreases everytime