If you could provide ANY help me with ANY of these statistics questions it would be greatly appreciated.
1. According to a poll 53% would vote for Mr. A. If a random sample of 100 people results in 45% who would vote for mr. A, test the claim that the actual percentage is 53% use .10.
2. Mean weight should be 30g = mu we suspect it is actually less than 30g. a sample of h=16 has mean=29.5g standard deviation =4.1. Test, with 0.5, the claim that the mean is less than 30g
3. use the given data to test the claim that mu1 is smaller than mu2 use .01. n1=85 /x1=189.1, s1=38.7, n2 = 75, /x2=203.7, s2=39.2.
4. Given = Cost 9,2,3,4,2,5,9,10
Number 85,52,55,68,67,86,83,73
Find: a) r
b. equation of regression line
c. use b to predict number if cost = 15
College Level Statistics Please Help?
1)H0: p=0.53
H1: p not 0.52
significance level 0.10
Sample proportion x/n = 0.53
Varaince of proportion = p*(1-p)/n
= 0.53(0.47)/100 =0.002491
S.D. of p is 0.0499
Z = (0.53 -0.45) / 0.0499 = -1.6029
|Z| does not exceed 1.64. Do not reject H0. Claim of OK at 10 % level of significance.
2)
H0: mu = 30
HA: mu not = 30
Sample mean 29.5
Standard deviation = 4.1
Standard error of mean = sd / sqrt(n)
SE = 4.1/4
Standard error of mean 1.025
z = (xbar-mu) /se
z = (29.5-30) / 1.025
z = -0.4878
This does not fall below -1.64 for a one-tailed test, so do not reject the hypothesis that mu=30g.
3)
H0: mu1=mu2
H1: mu1 %26lt; mu2
Sample 1 size 85
Sample 2 size 75
Sample 1 mean 189
Sample 2 mean 203.7
Sample 1 S.D. 38.7
Sample 2 S.D. 39.2
Pooled S.D = [(n1-1)s1^2+(n2-1)s2^2]/(n1+n2-2)
Pooled variance s = [(84)(1497.6900)+(74)(1536.64000))] / (158) = 1515.932405
Multiply s by sqrt(1/85+1/75) = 0.158423
Denominator of t = 6.16821943
t = (189 - 203.7) = -14.7 / 6.168219
t =-2.3832
Degree of freedom 158
.
With significance level 0.01, the critical t is -2.345
Computed t falls below the critical value.
Reject H0 and conclude H1.
4)
9 85 81 765
2 52 4 104
3 55 9 165
4 68 16 272
2 67 4 134
5 86 25 430
9 83 81 747
10 73 100 730
b = Σx[i]-xbar)*(y[i]-ybar) / sqrt[Σ(x[i]-xbar)^2 Σ(x[i]-xbar)^2]
regression coefficient is 2.7885
a = ybar - b*xbar
Constant a is 55.7885
number = 2.7885 cost +55.7885
plug cost =15 and predict number
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