At a large department store, the average number of years of service was 13.5 with a standard deviation of 6.2 years. If an employee is picked at random, what is the probability that the employee has worked for the company for over 12 years?
a. 0.0318
b. 0.0852
c. 0.1875
d. 0.2862
e. 0.4679
f. 0.6566
g. none of these
Statistical Problem Below... How do you solve?
Convert to a z-score.
z = (12 - 13.5) / 6.2 = -.24
Area to the right of that (greater than) = .5948
none of these. G
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