in a typical day, 22% of the people in the US with internet service go online to get the news. In a random sample of five people in the US with internet service, what is the probability that the number is going online to get the news is:
(A) Exactly two
(B) At least two
(C) At most two
Only 32% of cell phone users over 50 carry their cell phone switched on everyday. In a random sample of 10 users over 50 what is the probability that the number with their phone switch on is:
(A) Exactly five
(B) More than five
(C) Less than five
Prob and Stats questions (2) please help?
For the first, P(number going online for news is exactly k) is:
0 0.288717436800
1 0.407165616000
2 0.229683168000
3 0.064782432000
4 0.009135984000
5 0.000515363200
Just combine them and add them as needed.
Likewise, for the second:
0 0.0211392282015720880000
1 0.0994787209485745450000
2 0.2106608208322755200000
3 0.2643586771228556000000
4 0.2177071458658810800000
5 0.1229405059007328700000
6 0.0482119630983266210000
7 0.0129645615054323710000
8 0.0022878637950763010000
9 0.0002392537302040576300
10 0.0000112589990684262430
Reply:b
c
apricot
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